Error
Error Code:
53
MongoDB Error 53: Invalid Document ID Format
Description
This error indicates that an `_id` field in a document or an ID used in a query does not adhere to MongoDB's expected data types or format. It typically occurs during database operations like inserts, updates, or lookups when the provided identifier is malformed or incompatible.
Error Message
Invalid Id Field
Known Causes
3 known causesMismatched ID Data Type or Format
The ID provided for an operation does not match MongoDB's expected data type (e.g., `ObjectId`, string, number) or its specific format requirements.
Invalid ObjectId String Format
A string intended to represent an `ObjectId` was malformed, typically by having an incorrect length (must be 24 hexadecimal characters) or containing non-hexadecimal characters.
Querying with Malformed ID
An ID used within a query filter (e.g., `_id: 'invalid_id_value'`) does not conform to MongoDB's valid identifier formats, preventing the query from executing.
Solutions
3 solutions available1. Validate and Correct Document IDs medium
Inspect and fix malformed `_id` fields in your documents.
1
Identify the collection and documents that are causing the error. This often happens when trying to query or update a document with an invalid `_id`.
2
Connect to your MongoDB instance using the `mongo` shell or a GUI tool.
3
Use a query to find documents where the `_id` field might be malformed. MongoDB `_id` fields are typically `ObjectId` types. Look for non-string, non-ObjectId, or incorrectly formatted string `_id`s.
db.yourCollection.find({ _id: { $type: ['string', 'null', 'int', 'long', 'double', 'decimal', 'boolean', 'array', 'object', 'binData'] } })
4
For each identified malformed document, manually correct the `_id` field. If it's supposed to be an `ObjectId`, convert it. If it's a custom string ID, ensure it's a valid string.
db.yourCollection.updateOne({ _id: 'invalid_id_string' }, { $set: { _id: ObjectId('valid_object_id_string') } })
5
If you are inserting documents and receiving this error, ensure that the `_id` field, if provided, is either `null` (to let MongoDB generate an `ObjectId`) or a valid `ObjectId` string format before insertion.
db.yourCollection.insertOne({ _id: ObjectId('...') , field1: 'value1' });
// Or let MongoDB generate it
db.yourCollection.insertOne({ field1: 'value1' });
2. Check Application Code for ID Generation/Handling medium
Review your application's logic for how `_id`s are generated and used.
1
Examine the code responsible for inserting or updating documents in MongoDB. Pay close attention to how `_id` values are assigned.
2
Ensure that when you explicitly set an `_id`, you are using the correct MongoDB driver methods to generate or cast it to an `ObjectId` or a valid custom ID type.
const { ObjectId } = require('mongodb');
db.collection('yourCollection').insertOne({ _id: new ObjectId(), name: 'test' });
// Or for custom string IDs
db.collection('yourCollection').insertOne({ _id: 'my_custom_id_123', name: 'test' });
3
If your application is receiving `_id`s from an external source (e.g., user input, another API), validate and sanitize these IDs before using them in MongoDB operations. Ensure they conform to the expected `ObjectId` string format or your custom ID schema.
4
If you're using an ORM or ODM, consult its documentation for proper `_id` handling and ensure it's configured correctly.
3. Re-index Relevant Fields (If Custom IDs Are Used) easy
Ensure custom `_id` fields are properly indexed if they are not MongoDB's default `ObjectId`.
1
If you are using custom string or numerical values as your `_id` field, ensure it is properly indexed for efficient lookups.
2
Connect to your MongoDB instance.
3
Create an index on the `_id` field if it doesn't exist. This is usually done automatically by MongoDB, but it's good to verify, especially if you've changed ID types.
db.yourCollection.createIndex({ _id: 1 })
4
If you encounter issues with specific types of custom IDs (e.g., very long strings), consider if a different data type or a different approach to `_id` generation might be more suitable.